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Someone help me with my math homework!
"A rectangular garden is 12 ft by 5 ft. A gravel path of equal width is to be built around the garden. How wide can the path be if there is enough gravel for 138 ft²?"
A.) 3 ft
B.) 5 ft
C.) 4 ft
D.) 10 ft
This shit confuses me so much I actually put my answer on this test asking the instructor if it was a trick question. This is a retake. Everyone in the class got an F on this test, highest score was a 15/30 <.<
HELP ME 8WR!
 
Scitna said:
Someone help me with my math homework!
"A rectangular garden is 12 ft by 5 ft. A gravel path of equal width is to be built around the garden. How wide can the path be if there is enough gravel for 138 ft²?"
A.) 3 ft
B.) 5 ft
C.) 4 ft
D.) 10 ft
This shit confuses me so much I actually put my answer on this test asking the instructor if it was a trick question. This is a retake. Everyone in the class got an F on this test, highest score was a 15/30 <.<
HELP ME 8WR!
Click to expand...


Well the inside edge of the path has to measure 34 feel long (12+12+5+5) but beyond that I think it's been too long since I've had to do math stuff. Wait that's useless.


*thinking


**thinking



Ok, you have the garden which is 12 x 5 and the path around the outside is gonna be equal width all around so it's gonna look like this-
Area black.jpg

(Yes I know there are gaps and it isn't to proper scale, I havn't had breakfast yet and I just threw this together)

The area in black is actually the path so the white in the middle is the garden. To me it seems easier to separate it into different sections, figure out the area for those, and then add them to see if it equals the amount they said. So kinda like this-
Area color.jpg



First you need the length of each section of the walk. With the blue sections you are counting the extra length added to the garden by the walk itself so it is the length of that side of the garden (12) plus the width of the path (X) added twice, once for each side. (hence the x 2) For the other sides you don't have to add the extra length since I already included that area in the longer sides. So for each section it will be the length of that section times the width of the path so it should be (12 + X x 2) x X for the blue sections and 5 x X for the sections in red. You have two of each of those so you need to double both of them and then add them together. Whatever you end up with should equal 138.

So-
(((12 + X x 2) x X) x 2) + ((5 x X) x 2) = 138

The answer is 3 ft.
 
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